Mon Dec 07, 2015 11:26 am by GmdAquaman 


Three men in a cafe order a meal the total cost of which is $15. They each contribute $5. The waiter takes the money to the chef who recognizes the three as friends and asks the waiter to return $5 to the men.
The waiter is not only poor at mathematics but dishonest and instead of going to the trouble of splitting the $5 between the three he simply gives them $1 each and pockets the remaining $2 for himself.
Now, each of the men effectively paid $4, the total paid is therefore $12. Add the $2 in the waiters pocket and this comes to $14.....where has the other $1 gone from the original $15? :idea: :?: :?: :!: :?: :!: :!: :twisted: :evil: 




Sat Dec 19, 2015 1:22 am by ac4pic 


3x = 15 (gave it to the waiter > gives it to the chef)
x = 5 (each paid)
3x = 10 (chef got this much left)
x = 3.33.... (each one of them paid to the chef)
The chef is done with.
Now, how much do you pay the waiter?
(They each pay 2 dollars)
3x = 2
x = (2/3)
Each pay 66 cents to the waiter.
((chef) + (waiter))/3 = (total paid per person)
3.33 + .66 = 4 dollars
They paid in total 4 dollars.
3x = 12
Now, they get the remaining 3 dollars. :D So, they saved 1/5 the money. Everyone wins! :D 




Sat Jan 07, 2017 11:21 am by Saiyan0414 


The men paid a total of 12$ and the waiter keeps 2$ for himself. Also when the chef returned 5$ back he is left with 10$.
therefore, 10$(chef) + 2$(waiter) = 12$ paid by the 3 men.[/list] 






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